00:01
Heat is a form of energy that flows from a hotter to a colder body.
00:04
The heat that is associated with temperature change is solved as q equals m -c, delta -t, where q is the heat, m is the mass, c is the specific heat, and delta -t is the change in temperature that is solved from the difference between the final temperature tf and the initial temperature t -i.
00:19
In this problem, we're given with the 50 gallons of water that is being heated so that its temperature rises from 20 degrees celsius to 53 degrees celsius.
00:30
If the heater that is used to heat it operates with a power rating of 5 ,800 watts, we want to find the amount of time it takes to heat the said amount of water, assuming that no heat is lost, or that is the heater is well insulated, and that also no water is withdrawn from the tank during the time of heating.
00:53
So first is that we will compute the heat.
00:57
So for that, we will be needing the mass.
01:00
Assume that water has a density of one gram per m l then we can solve for the mass by simply multiplying the density by the volume since density will be expressed in grams per ml we will be converting gallons to m l noting that one gallon is equal to 3 ,785 ml.
01:26
Therefore, 50 gallons in ml is going to be equal to 189 ,250.
01:37
And so we have 1, that's the density times 189 -250 that gives us the same value, which is 189 -250 at this time in grabs...