00:01
So for this particular question, how many acres of each crop should the farmer plan to maximize our profit? so let farmer uses x acres of land for crop a.
00:19
Let farmer uses x acres of land for crop a.
00:35
Then 60 minus acres for a temporary that 60 minus x acres of land for crop b then cost of crop a cost of crop a is equal to 25 times x and same for crop b will be 50 times 60 minus x dollars correct total cost total cost is 25x plus 50 times 60 minus x dollars okay so this should be less than is equal to 2 ,750.
01:43
It implies that 3000 minus 25 x tester is equal to 2750.
01:58
It says that 25x must be greater than is equal to 3 ,000 minus 2750 which is nothing but from here if you will do we'll get x should be greater than is equal to given profit on crop a given we have profit on crop a is equal to 90x and that on crop b we have 150 times 60 minus x so total profit is scroll total profit p of x is equal to 90x plus 99 ,000 know, yeah, 9 ,000 minus 60x.
03:22
So this is to be maximized.
03:28
Profit we have to maximize.
03:30
So let's compare p of x with y is equal to mx plus c.
03:41
Oh let me just solve it.
03:46
P of x is equal to 9 ,000 minus 60x...