A fielder tosses a 0.15 kg baseball at 27 m/s at a 27° angle to the horizontal. Part A What is the ball's kinetic energy at the start of its motion? Express your answer with the appropriate units. Ki = Part B What is the kinetic energy at the highest point of its arc? Express your answer with the appropriate units. Kpeak =
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15 \, \text{kg} \) and \( v = 27 \, \text{m/s} \). \[ K_i = \frac{1}{2} \times 0.15 \, \text{kg} \times (27 \, \text{m/s})^2 \] \[ K_i = \frac{1}{2} \times 0.15 \times 729 \] \[ K_i = 54.675 \, \text{J} \] Show more…
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