00:01
So, in this problem length of the resistance, so length of the resistance, resistance which is given p is l, right and length of the resistance q and length of the resistance q is 2l.
00:46
So, these are the things that have been given.
00:48
So, diameter of the wire p is next diameter of the wire.
00:57
So, diameter of the wire p is what i have is d by 2 and diameter of wire q is d.
01:08
So, which is my diameter of wire q is d and current through the wire p is i1 and current through the wire q is i2.
01:24
And again current through the wire is sorry current through the wire p is i1 and current through the wire q is i2.
01:56
So, these are the things that i have given.
01:58
So, to find the ratio of i1 divided by i2.
02:01
So, i have to i got to find i1 divided by i2.
02:12
So, that is the ratio that i have been asked to find.
02:16
So, these are my given conditions.
02:19
So, now i will proceed forward with my idea that the radius of wire p is.
02:25
So, the radius of wire p is r1 which is d by 2 divided by 2 which is going to be d divided by 4.
02:44
So, the cross sectional area of wire p is now the cross sectional area of wire p, wire p is which is basically a1 equals to pi r1 square equals to pi which is d divided by 4 that is square which results pi d square divided by 16.
03:22
So, pi d square divided by 16 the resistance of the wire p is given by expression.
03:29
So, now my the resistance of wire p, wire p is given that is my r1 which is something like rho l divided by a, a is the area.
03:56
So, what i will get is rho l.
03:58
So, what i will get is rho times l divided by pi d square.
04:04
So, divided by pi d square divided by 16...