A firm maintains 22 cars for business purposes. From past experience, it is known that approximately 10% will require major engine service during a one-year period. What is the probability that at most 1 car will require major engine repair next year? 0.0480 0.2407 0.6608 0.9520 0.3392
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Using the binomial distribution formula, we have: P(X=0) = 22C0 * (0.10)^0 * (0.90)^(22-0) P(X=0) = 1 * 1 * 0.90^22 P(X=0) ≈ 0.0480 Show more…
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