Question

$P_X(x) = \begin{cases} 0.1 & \text{for } x = 0.2 \\ 0.2 & \text{for } x = 0.4 \\ 0.2 & \text{for } x = 0.5 \\ 0.3 & \text{for } x = 0.8 \\ 0.2 & \text{for } x = 1 \\ 0 & \text{otherwise} \end{cases}$

          $P_X(x) = \begin{cases} 0.1 & \text{for } x = 0.2 \\ 0.2 & \text{for } x = 0.4 \\ 0.2 & \text{for } x = 0.5 \\ 0.3 & \text{for } x = 0.8 \\ 0.2 & \text{for } x = 1 \\ 0 & \text{otherwise} \end{cases}$

PX(x) = 0.1 for x = 0.2
0.2 for x = 0.4
0.2 for x = 0.5
0.3 for x = 0.8
0.2 for x = 1
0 otherwise

Added by Jeffrey B.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Sri K

03/13/2023

Step 1

In this case, the possible values of X are 0.2, 0.4, 0.5, 0.8, and 1. Therefore, Rx = {0.2, 0.4, 0.5, 0.8, 1}. Show more…

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A.) Find Rx, the range of the random variable X B.) Find P(X<=0.5) C.) Find P(0.25P_(x)(x)={(0.1 for x=0.2),(0.2 for x=0.4),(0.2 for x=0.5),(0.3 for x=0.8),(0.2 for x=1),(0 otherwise ):} 0.1 0.2 0.2 0.3 0.2 for x = 0.2 for x = 0.4 for x = 0.5 for x = 0.8 for x=1 Px(x) otherwise