00:01
In this problem, we are given the function f of theta equals 6 sine theta plus 2 cosine theta on the interval from negative 2 pi to 2 pi.
00:08
Our job is to find the critical points on that interval, to identify the local maximum and minimum points, and to determine the absolute maximum and minimum values.
00:17
So we start on critical points by finding the critical numbers, which means we have to take the derivative.
00:22
So we've taken the derivative of the given function.
00:25
That derivative is 6 cosine theta minus 2 sine theta.
00:29
That exists for all real numbers theta, so the critical numbers occur when the derivative is zero.
00:35
So we're going to solve this equation for values of theta in the original interval.
00:43
And so we see that we want all values of theta in that interval, where tangent of theta equals three.
00:50
One of those values is tangent inverse of three, which turns out to be approximately 1 .249.
01:03
To get the others, we will add and subtract values of pi.
01:09
And so we're going to have four values in all.
01:13
We will give the approximations for those here.
01:18
So adding and subtracting pi and staying within that interval, we see that each of these four values rounded to three decimal places will be a critical number in the interval.
01:36
Now, once we get those, we want to find the y coordinates that correspond to these theta coordinates.
01:43
And so to do that, we have f of theta values in each case.
01:55
We'll just write these underneath.
01:57
We're going to sketch the graph in just a second...