(a) Find the length of the arc that subtends the given central angle $\theta$ on a circle of diameter $d$ (b) Find the area of the sector determined by $\boldsymbol{\theta}$. $$\theta=50^{\circ}, \quad d=16 \mathrm{m}$$
Added by Edward W.
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In this case, $\theta = 50^\circ$ and $r = \frac{d}{2} = \frac{16}{2} = 8$ m. Plugging in these values, we get: $$S = \frac{50}{360} \times 2\pi \times 8 = \frac{5}{36} \times 16\pi \approx 6.98 \text{ m}$$ Show more…
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