00:01
In this problem, we have been given that there is a satellite and this is orbiting such that its distance from the surface of earth that is 3 .58 into 10 raised to 7 meters.
00:15
So let's take this distance as edge here and we have been given the radius of earth as well as the mass of the earth and we are required to figure out the orbital speed of the satellite.
00:26
So we use the expression root gm by r to compute the orbital speed.
00:31
So putting the values here, we can get root of g, which is the universal gravitational constant, that's 6 .67 into 10 raise to minus 11, multiplied by the mass of the earth.
00:43
That's 5 .97 into 10 raise to 24, divided by r.
00:49
And r here is the distance between the two centers.
00:53
So with respect to the earth center, the distance of the satellite, that will be the radius of the earth and the height from the surface.
01:02
So that comes out to be 4 .22 into 10 raise to 7.
01:09
And from here we observe that on simplification, the orbital speed comes out to be approximately 3 .1 kilometers per second.
01:20
And in the next case, we have to determine the time period of revolution of this satellite provided that the orbital radius is doubled.
01:29
So here we have the expression for the time period.
01:32
So we can square this expression and we observe that if all the other things are constant, which is in this given situation...