2. A first order system has transfer function $G(s) = \frac{10}{s+10}$ \newline Calculate the gain and phase of this transfer function when $u = 2 \sin(10t)$ is the input.\newline Gain = dB (10 pts) \newline Phase = degrees
Added by Daniel W.
Close
Step 1
The gain of a transfer function is the magnitude of the transfer function evaluated at s = jω, where ω is the frequency of the input signal. In this case, the input signal is u = 2 sin(10t), so the frequency is 10 rad/s. To find the gain, we substitute s = jω Show more…
Show all steps
Your feedback will help us improve your experience
Dwijendra Rao and 87 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
2. (20 points) Consider a second-order system whose transfer function is G(s) = Y(s)/U(s) = 10/((s+1)(s+2)), where U(s) and Y(s) are the Laplace transforms of the input u(t) and the output y(t), respectively. The initial conditions are zero, i.e., y(0) = 0 and y'(0) = 0. (a) (10 points) Suppose that the input u(t) = A+5e^-t (A : constant) is applied to this system. Determine the value of A such that the final output (y(∑) = lim y(t) as t→∑) is 50. (b) (10 points) Now, the input u(t) = sin(t) is applied to this system. Determine the maximum amplitude of the steady-state output (i.e., the output after a sufficiently large amount of time).
Adi S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Watch the video solution with this free unlock.
EMAIL
PASSWORD