00:01
Hello students, in this question we have provided a fixed end beam.
00:06
So, a fixed end beam means it is restricted in the both ends and cannot move.
00:15
So, it is a fixed end beam.
00:17
As we can see that in the figure, the reactions are marked as r a, r b and q is the uniform load of intensity that is given.
00:32
So, we have to calculate the deflection curve equation first, then the bending moment, then the slope, deflections and maximum bending moment.
00:45
So, in the case of this figure, the maximum bending moment occurs at the midpoint.
00:55
So, we have maximum bending moment occur at mid of the beam.
01:04
Now, we can solve for the reaction values.
01:07
So, using the differential equation that is dou square y by dou x square will be equal to mx by e into i.
01:21
So, by force balance equation, we can calculate that r a plus r b, the reaction sum will be equal to the load into length multiplied with r a which is equal to r b that is equal to q l by.
01:42
So, now when we take the moment at x, we can write mx will be equal to reaction ax minus m a minus the load q x square by 2.
02:02
So, we have mx will be equal to q into l x by 2, r a is q l by 2 minus m a minus q x square by 2.
02:18
So, solving that we have mx q by 2 into l x minus x square minus moment at a...