A flashlight has 6 batteries, 2 of which are defective, if 2 are selected at random without replacement find the probability that both of them are defective?
Added by Donald A.
Step 1
This can be calculated using the combination formula, which is C(n, r) = n! / [(n-r)! * r!], where n is the total number of items, r is the number of items to choose, and "!" denotes factorial. So, the total number of ways to select 2 batteries out of 6 is C(6, Show more…
Show all steps
Close
Your feedback will help us improve your experience
Thuc Nguyen and 78 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A flashlight has 6 batteries, 4 of which are defective. If 4 are selected at random without replacement, find the probability that all of them are defective. Enter your answer as a fraction or a decimal rounded to 3 decimal places. The probability of getting all of them defective batteries is
Audrey F.
A flashlight has 6 batteries, 2 of which are defective. If 2 are selected at random without replacement, find the probability that both are defective: 1/2 1/6 1/15 1/100
Adi S.
Defective Batteries In a box of 12 batteries, 2 are dead. If 2 batteries are selected at random for a flashlight, find the probability that both are dead. Would you consider this event likely or unlikely?
Probability and Counting Rules
The Multiplication Rules and Conditional Probability
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD