00:02
For part a, we are asked to figure out the maximum induced voltage in the coil when the number of turns is 1 ,000, and the magnetic field perpendicular to the axis of rotation is 0 .2 tesla.
00:17
We're told that the area is 0 .1 meters squared, and it's rotating at 60 revolutions per second, which converted to radiance by multiplying by 2 pi is 376 .8 radiance per second.
00:29
Okay, so the induced voltage will indicate this as part a is equal to the number of turns in the coil times the magnetic field times the area multiplied by omega times the sine of omega times time.
01:00
Well, since the sign of a value gives you a number between zero and one, this is maximum.
01:11
When sine of omega -t is 1.
01:14
So we can say max at sine omega -t equal to 1.
01:34
Therefore, we can say e -max is equal to the number of turns multiplied by the magnetic field, multiplied by the area, multiplied by omega.
01:55
Plugging those values into this expression, we find that this is equal to 7 .5 times 10 to the 3rd volts or 7 .5 kilowolts, since 10 to the 3rd is equal to a kilowolt...