00:01
So, here it is given that for approved product, the initial temperature t i equals to minus 1 .75 degrees celsius, environment temperature let's say t 2 equals to minus 25 degrees celsius.
00:14
So, after 15 hours, the temperature becomes t is equals to minus 10 degrees celsius.
00:21
So, basically here the time will be equals to 15 hours, let us convert in second.
00:26
So, 15 multiplied by 3600 of second, so will comes out equals to 54 ,000 of second.
00:36
So, heat transfer coefficient is we have to find here let's say h is equals to question mark, for that diameter we have been given 10 centimeter which will be equals to 0 .1 of meters and density is we have given for water 1000 kg per meter cube.
00:53
So, let us start with the concept which we are going to use for this question will be the required formula of thermal heat transfer or heat transfer coefficient.
01:03
So, that can be given by let us say that t h a divided by the rho c p times of v, this should be equals to the ln of into the bracket t i minus t 2 divided by t minus of t 2, where v is the volume area is specific for the foot which is known to us.
01:27
So, let me write down this here, cp is equals to 4 .18 kg per kilojoules...