Question

2. a) For the inlet area of the wind tunnel the air pressure would be at atmospheric pressure. 1.001 x 10$^5$ N/m$^2$. What would be the Pitot tube pressure differential (in N/m$^2$) in the test- section of the wind tunnel if the wind speed there is 120 miles per hour. Yes, I am giving you mixed units. b) What would be the Pitot tube pressure (in N/m$^2$) in the test section if the wind speed was the value found in problem 1. (They call that double jeopardy.)

          2. a) For the inlet area of the wind tunnel the air pressure would be at atmospheric pressure.
1.001 x 10$^5$ N/m$^2$. What would be the Pitot tube pressure differential (in N/m$^2$) in the test-
section of the wind tunnel if the wind speed there is 120 miles per hour. Yes, I am giving you
mixed units.
b) What would be the Pitot tube pressure (in N/m$^2$) in the test section if the wind speed was
the value found in problem 1. (They call that double jeopardy.)

2. a) For the inlet area of the wind tunnel the air pressure would be at atmospheric pressure.
1.001 x 10^5 N/m^2. What would be the Pitot tube pressure differential (in N/m^2) in the test-
section of the wind tunnel if the wind speed there is 120 miles per hour. Yes, I am giving you
mixed units.
b) What would be the Pitot tube pressure (in N/m^2) in the test section if the wind speed was
the value found in problem 1. (They call that double jeopardy.)

Added by Rodney G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

11/15/2023

Step 1

1 mile per hour is approximately 0.44704 meters per second. Therefore, 120 miles per hour is equal to 120 * 0.44704 = 53.6448 meters per second. Show more…

Show all steps

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a) For the inlet area of the wind tunnel, the air pressure would be at atmospheric pressure, 1.001 x 10^5 N/m^2. What would be the Pitot tube pressure differential (in N/m^2) in the test section of the wind tunnel if the wind speed there is 120 miles per hour? Yes, I am giving you mixed units. b) What would be the Pitot tube pressure (in N/m^2) in the test section if the wind speed was the value found in problem 1? (They call that double jeopardy.) 2. a) For the inlet area of the wind tunnel, the air pressure would be at atmospheric pressure, 1.001 x 10^5 N/m. What would be the Pitot tube pressure differential (in N/m) in the test section of the wind tunnel if the wind speed there is 120 miles per hour? Yes, I am giving you mixed units. b) What would be the Pitot tube pressure (in N/m) in the test section if the wind speed was the value found in problem 1? (They call that double jeopardy.)