00:01
Hello everyone we are going to understand this question here given in the question given force at p is equal to force at p that is given 2500 newton length of beam length of beam l is equal to 11 meter distance between a and b distance between a and b that is between a and b that is given 8 meter and mass of the beam mass of beam m is equal to 80 kg now in the part c we have to calculate the we have to draw the three body diagram for this question from this fvd we can see that here from the point b there will be a normal reaction that is represented by nb and from the point a, there is normal reaction that is represented by an a.
01:45
And here, weight of the rod is working at the midpoint of the rod that is 80.
01:59
So, midpoint of the rod, that is at t.
02:03
And here total length of the beam is 11 meter and given a, b is given 8 meter.
02:10
It means weight of the rod is at this point at midpoint that is at t at t g let it is represented by o so now taking the vertical and horizontal component of n b so vertical component of nb is that is n b sine theta n b sine theta for sine 60 n b sign and horizontal component of nb that is nb cos 60 x xn b and b sine 60 and b coss 60 and b coss 60 now equating vertical and horizontal force equating vertical and horizontal force and horizontal force so we can write here vertical force is 80g is working vertically downward plus p is also working vertically downward and nb sine theta is working vertically upward nb sine theta nb sine 60 that is equal to 0 so we can write nb sine 60 is equal to 80g plus value of p that is given in the question that is 2 ,500 so vertical component is 80g plus 2500.
04:38
Let this is equation 1 and force along y -axis.
04:48
So this is the force along y -axis, force along y -axis, now force along x -axis.
05:10
So we can write, we can write nb cost 60, nb cost 60 minus n -n -e.
05:26
Is equal to 0 or we can write n a is equal to n b cost 60 let this is equation 2 now substituting the value of p in equation so sorry here doing the calculation in equation 1 so after calculation we will get n b is equal to 80 g plus 2500 upon sine 60...