A force F of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 m. If F is perpendicular to the 4 m displacement, the work it does is equal to (A) 0 J (B) 60 J (C) 80 J (D) 600 J
Added by Albert S.
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Step 1: Given force F = 20 N, mass = 3 kg, displacement = 4 m, and force is perpendicular to displacement. Show more…
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A force F of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 m. If F is perpendicular to the 4 m displacement, the work it does is equal to (A) oJ (B) 60 $\mathrm{J}$ (C) 80 $\mathrm{J}$ (D) 600 $\mathrm{J}$
A force $\vec{F}=(3.00 \mathrm{N}) \hat{\mathrm{i}}+(7.00 \mathrm{N}) \hat{\mathrm{j}}+(7.00 \mathrm{N}) \hat{\mathrm{k}}$ acts on a 2.00 $\mathrm{kg}$ mobile object that moves from an initial position of $\vec{d}_{j}=(3.00 \mathrm{m}) \hat{\mathrm{i}}-(2.00 \mathrm{m}) \hat{\mathrm{j}}+(5.00 \mathrm{m}) \hat{\mathrm{k}}$ to a final position of $d_{f}=-(5.00 \mathrm{m}) \hat{\mathrm{i}}+(4.00 \mathrm{m}) \hat{\mathrm{j}}+(7.00 \mathrm{m}) \hat{\mathrm{k}}$ in 4.00 $\mathrm{s} .$ Find $(\mathrm{a})$ the work done on the object by the force in the 4.00 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors $\vec{d}_{i}$ and $\vec{d}_{f}$
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