Question

A force of 10 N moves a block of mass 2.5 kg along a horizontal table by 4.5 m. The block starts from rest and the coefficient of friction between the block and table is 0.25. What is the net work done on the block?

Name: a force of 10 n moves a block of mass 25 kg along a horizontal table by 45 m the block starts from rest and the coefficient of friction between the block and table is 025 what is the net wor 79625
Uploaded: 2021-12-09T20:21:24-08:00
Duration: 3 min 52 s
Channel: Dwijendra Rao
Description: a force of 10 n moves a block of mass 25 kg along a horizontal table by 45 m the block starts from rest and the coefficient of friction between the block and table is 025 what is the net wor 79625

          A force of 10 N moves a block of mass 2.5 kg along a horizontal
table by 4.5 m. The block starts from rest and the coefficient of
friction between the block and table is 0.25. What is the net work
done on the block?

Added by Seth G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Dwijendra Rao

12/09/2021

Step 1

The gravitational force \( F_g \) is given by the formula: \[ F_g = m \cdot g \] where \( m = 2.5 \, \text{kg} \) is the mass of the block and \( g = 9.8 \, \text{m/s}^2 \) is the acceleration due to gravity. \[ F_g = 2.5 \, \text{kg} \times 9.8 \, Show more…

Show all steps

Thanks for your feedback!

A force of 10 N moves a block of mass 2.5 kg along a horizontal table by 4.5 m. The block starts from rest and the coefficient of friction between the block and table is 0.25. What is the net work done on the block?