A force of 10.0 N is applied at an angle of 30° to the horizontal on a 1.25-kg block initially at rest on a frictionless surface. (a) what is the magnitude of the block's acceleration? (b) what is the magnitude of the normal force?
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** The horizontal component of the force is given by: $F_x = F \cos \theta = 10.0 \text{ N} \cos 30^\circ = 8.66 \text{ N}$ The vertical component of the force is given by: $F_y = F \sin \theta = 10.0 \text{ N} \sin 30^\circ = 5.00 \text{ N}$ Show more…
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