00:01
So here we have been given the three boxes and the mass of these three boxes are 1 .3 kg for this box, 3 .2 kg for this box, and 4 .9 kg for the third box.
00:16
And here a force of 7 .5 newton is applied to the box like this.
00:23
And we need to figure out the contact force which exists between box 1 and 2 .3 .2.
00:32
2.
00:33
So this is box 1, this is box 2, this is box 3.
00:37
So first we will figure out the contact force between 1 and 2.
00:42
So here if we draw the free body diagram, this is box 3 here.
00:50
So when we draw the free body diagram, we can be able to get the force of basically the contact force between each boxes.
01:00
So let's say the contact force between box 1 and 2 is n1.
01:04
And between box 2 and 3 it's n2 so first we draw the free body diagram and before that let's figure out the acceleration the net force here is 7 .5 newtons and the total mass of the system that is approximately 1 .3 plus 3 .2 plus 4 .9 it is 9 .4 kilograms so from here we can compute the acceleration and that acceleration will be approximately 0 .79.
01:40
So it will be 0 .8 meter per second square approximately.
01:46
So now we draw the free body diagram.
01:48
So for object 3, there is a force of 7 .5 newtons, which is applied to the left direction here.
01:57
And on this block, there is a contact force which is acting and that will be n2.
02:04
Now there are also vertical forces...