A frictionless inclined plane is 13.0 m long and 5.00 m high. What is the IMA of the inclined plane and how much gravitational force can be overcome by exerting a force of 375 N
Added by Philip T.
Step 1
Given: Length (L) = 13.0 m Height (H) = 5.00 m IMA = 13.0 m / 5.00 m IMA = 2.6 Show more…
Show all steps
Your feedback will help us improve your experience
Narayan Hari and 86 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An inclined plane is 10.0 m long and 2.50 m high. (a) Find its mechanical advantage. (b) A resistance of 727 N is pushed up the plane. What effort is needed? (c) An effort of 200 N is applied to push an 815 N resistance up the inclined plane. Is the effort enough?
Emily A.
A block of mass m = 10.5 kg rests on an inclined plane with a coefficient of static friction of ?s = 0.11 between the block and the plane. The inclined plane is L = 6.8 m long and it has a height of h = 3.4 m at its tallest point. What is the component of the force of gravity along the plane, Fgx in newtons?
Madhur L.
A block of mass $5.00 \mathrm{~kg}$ is sliding at a constant velocity down an inclined plane that makes an angle of $37.0^{\circ}$ with respect to the horizontal. a) What is the friction force? b) What is the coefficient of kinetic friction?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD