00:01
In this problem, we'd like to find the temperature rise, the total flow rate, the torque, and the power dissipated.
00:07
So we're given our nominal diameter, which is d as 60 millimeters.
00:12
We have our bearing length as 30 millimeters.
00:15
We have our load as 3 .2 kiloons, and our speed as 3 ,200 rpm, as well as our room temperature.
00:25
To calculate the power dissipate in the bearing, our power is going to be our load, divided by ld.
00:32
We plug in 3 .2 times 10 to the 3 divided by 30 times 60.
00:39
And so we get our power dissipated as 1 .77 newton's per meter squared.
00:45
Now we'd also like to find, we have our power dissipated.
00:51
We can also find our value for v.
00:55
We have v as pi d n over 60...