00:01
We'd like to determine the rate at which heat must be supplied, so we'd like to find q.
00:07
Okay, so if we consider a three surface enclosure, then due to symmetry, we're going to have q3 equal to zero, q1 is equal to negative q21, since the heat lost by 1 is the heat gained by 2.
00:25
So we can go ahead and find an expression for our q dot.
00:31
We have q1.
00:32
We have q1.
00:32
Dot, which is our flow rate, is equal to this energy at the surface b1 minus the energy at the surface b2, divided by our 1 minus emissivity 1, divided by area 1 emissivity 1, plus area 1 f12, plus 1 over area 1, f1 3, plus area 2, f23, all to the negative 1 power.
01:01
Now, f -1 -3 is equal to f -12, which is equal to f -23, which is equal to 0 .5, by symmetry...