Given:
- Mass of flywheel, \( m = 370 \, kg \)
- Radius of flywheel, \( r = 0.50 \, m \)
- Angular velocity, \( \omega = 400 \pi \, rad/s \)
Calculate:
\( I = \frac{1}{2} \times 370 \times (0.50)^2 = 46.25 \, kg \cdot m^2 \)
\( KE = \frac{1}{2} \times 46.25
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