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A galvanic cell is constructed by placing a strip of nickel into a 1.0 M solution of nickel nitrate and a strip of iron into a 1.0 M solution of iron nitrate. The two metal strips are connected to a voltmeter by platinum wires and a salt bridge connects the solutions. See the diagram below. The temperature is 25 °C. The following standard reduction potentials apply: Fe3+(aq) + 3e? ? Fe(s) E° = ?0.040 V Ni2+(aq) + 2 e? ? Ni(s) E° = ?0.257 V Pt wire salt bridge Ni(s) Fe(s) Ni(NO3)2(aq) Fe(NO3)3(aq) Use the information above to answer the following three questions (A to C). A: What is E° for the cell? (Enter a value accurate to three significant figures). B: Which of the following statements is/are correct? (Select all that apply). - The nickel electrode is the cathode. - The Fe electrode increases in mass and the Ni electrode decreases in mass. - Electrons flow from the Fe electrode through the platinum wire towards the Ni electrode. - Positive ions in the salt bridge diffuse towards the nickel nitrate solution. - The iron electrode is the cathode. C: What is Ecell when the cell described above reaches equilibrium?

          A galvanic cell is constructed by placing a strip of nickel into a 1.0 M solution of nickel nitrate and a strip of iron into a 1.0 M solution of iron nitrate. The two metal strips are connected to a voltmeter by platinum wires and a salt bridge connects the solutions. See the diagram below. The temperature is 25 °C. The following standard reduction potentials apply:
Fe3+(aq) + 3e? ? Fe(s) E° = ?0.040 V
Ni2+(aq) + 2 e? ? Ni(s) E° = ?0.257 V

Pt wire
salt bridge
Ni(s)
Fe(s)
Ni(NO3)2(aq)
Fe(NO3)3(aq)

Use the information above to answer the following three questions (A to C).
A: What is E° for the cell? (Enter a value accurate to three significant figures).

B: Which of the following statements is/are correct? (Select all that apply).
- The nickel electrode is the cathode.
- The Fe electrode increases in mass and the Ni electrode decreases in mass.
- Electrons flow from the Fe electrode through the platinum wire towards the Ni electrode.
- Positive ions in the salt bridge diffuse towards the nickel nitrate solution.
- The iron electrode is the cathode.

C: What is Ecell when the cell described above reaches equilibrium?

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A galvanic cell is constructed by placing a strip of nickel into a 1.0 M solution of nickel nitrate and a strip of iron into a 1.0 M solution of iron nitrate. The two metal strips are connected to a voltmeter by platinum wires and a salt bridge connects the solutions. See the diagram below. The temperature is 25 °C. The following standard reduction potentials apply:
Fe3+(aq) + 3e? ? Fe(s) E° = ?0.040 V
Ni2+(aq) + 2 e? ? Ni(s) E° = ?0.257 V

Pt wire
salt bridge
Ni(s)
Fe(s)
Ni(NO3)2(aq)
Fe(NO3)3(aq)

Use the information above to answer the following three questions (A to C).
A: What is E° for the cell? (Enter a value accurate to three significant figures).

B: Which of the following statements is/are correct? (Select all that apply).
- The nickel electrode is the cathode.
- The Fe electrode increases in mass and the Ni electrode decreases in mass.
- Electrons flow from the Fe electrode through the platinum wire towards the Ni electrode.
- Positive ions in the salt bridge diffuse towards the nickel nitrate solution.
- The iron electrode is the cathode.

C: What is Ecell when the cell described above reaches equilibrium?

Added by Ashley C.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

03/20/2023

Step 1

Since the standard reduction potential for Fe is higher than that for Ni, Fe will be reduced and Ni will be oxidized. The half-reactions are: Fe³⁺(aq) + 3e⁻ → Fe(s) E° = -0.040 V (reduction) Ni(s) → Ni²⁺(aq) + 2e⁻ E° = -0.257 V (oxidation) Now, we need to Show more…

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A galvanic cell is constructed by placing a strip of nickel into a 1.0 M solution of nickel nitrate and a strip of iron into a 1.0 M solution of iron nitrate. The two metal strips are connected to a voltmeter by platinum wires and a salt bridge connects the solutions. See the diagram below. The temperature is 25 °C. The following standard reduction potentials apply: Fe3+(aq) + 3e− ⇌ Fe(s) E° = −0.040 V Ni2+(aq) + 2 e− ⇌ Ni(s) E° = −0.257 V Pt wire salt bridge Ni(s) Fe(s) Ni(NO3)2(aq) Fe(NO3)3(aq) Use the information above to answer the following three questions (A to C). A: What is E° for the cell? (Enter a value accurate to three significant figures). B: Which of the following statements is/are correct? (Select all that apply). - The nickel electrode is the cathode. - The Fe electrode increases in mass and the Ni electrode decreases in mass. - Electrons flow from the Fe electrode through the platinum wire towards the Ni electrode. - Positive ions in the salt bridge diffuse towards the nickel nitrate solution. - The iron electrode is the cathode. C: What is Ecell when the cell described above reaches equilibrium?

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Transcript

00:01 Hello students let's begin with this question this question is based upon the galvanic cell its composition is given in the question and reactions are also given.

00:09 The reactions are the galvanic cell is composed of the iron and nickel so this is the reaction and the e note for this reaction is minus 0 .040 volt and second one is nickel 2 positive plus 2 electron it will form nickel and its e note is also given in the question which is equal to minus 2 .0 .25 volt and let's solve the a part.

00:38 In the a part we have to find out the e knot of the cell.

00:42 So the formula used to find out the e note of the cell is e .0 cell is equals to the reduction potential of the reaction that is occurring at the cathode minus the reduction potential of the reaction that is occurring at the anode.

01:03 Now from the given reactions, this nickel, this nickel, this reaction is occurring at the cathode.

01:18 And this iron is occurring at the anode.

01:23 Now here the reduction potential of this nickel is 0 .25 minus minus 0 .0 .0.

01:34 So when we find out this, we get the e0 cell.

01:37 So e not of the cell should be e .0 cell is equal to minus 0 .27 volt.

01:46 Now in the next part, we have to answer the given statement.

01:51 Either the given statements are correct or not.

01:54 So the first part is asking about that the nickel is a the nickel is at the cathode.

02:05 The nickel electrode is at cathode.

02:14 The cathode is where the reduction occurs.

02:21 So in this case, n2 positive is reduced to.

02:26 Nickel.

02:28 So the first statement is the true.

02:32 This is true, true that nickel electrode is at cathode.

02:44 This is the correct statement.

02:47 Now the second statement is the iron electrode increases in mass and the nickel electrode decreases in mass.

02:55 So the answer of this part is this is incorrect.

02:59 Because this statement, this one is the first statement, this one is the second statement...

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