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A gambler has the following strategy when playing the roulette: ? she bets 1 dollar on red and if she wins she stops, ? if she loses, she bets 2 dollars on red and then stops. The roulette has 38 numbers from which 0 and 00 are green and the rest are red or black. When a gambler bets on red, the gambler wins if the ball stops at any of the red numbers. In addition, the payout when betting on colors is 1:1 (i.e. if one wins, one gets back double the money one bet). a) Find the probability she loses 3 dollars. b) Find the probability she won on the first bet given that she made 1 dollar. c) If X is the amount of money she won, find E[X]. d) Suppose the gambler changes her strategy and now bets 1 dollar every time on red and never stops. So, on every bet she either wins or loses a dollar. Find the expected number of bets she will make till she wins at least 3 out of 4 consecutive bets.

          A gambler has the following strategy when playing the roulette:

? she bets 1 dollar on red and if she wins she stops,

? if she loses, she bets 2 dollars on red and then stops.

The roulette has 38 numbers from which 0 and 00 are green and the rest are red or black. When a gambler bets on red, the gambler wins if the ball stops at any of the red numbers. In addition, the payout when betting on colors is 1:1 (i.e. if one wins, one gets back double the money one bet).

a) Find the probability she loses 3 dollars.

b) Find the probability she won on the first bet given that she made 1 dollar.

c) If X is the amount of money she won, find E[X].

d) Suppose the gambler changes her strategy and now bets 1 dollar every time on red and never stops. So, on every bet she either wins or loses a dollar. Find the expected number of bets she will make till she wins at least 3 out of 4 consecutive bets.
        
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A gambler has the following strategy when playing the roulette:

? she bets 1 dollar on red and if she wins she stops,

? if she loses, she bets 2 dollars on red and then stops.

The roulette has 38 numbers from which 0 and 00 are green and the rest are red or black. When a gambler bets on red, the gambler wins if the ball stops at any of the red numbers. In addition, the payout when betting on colors is 1:1 (i.e. if one wins, one gets back double the money one bet).

a) Find the probability she loses 3 dollars.

b) Find the probability she won on the first bet given that she made 1 dollar.

c) If X is the amount of money she won, find E[X].

d) Suppose the gambler changes her strategy and now bets 1 dollar every time on red and never stops. So, on every bet she either wins or loses a dollar. Find the expected number of bets she will make till she wins at least 3 out of 4 consecutive bets.

Added by Michael K.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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A gambler has the following strategy when playing the roulette: * she bets 1 dollar on red and if she wins she stops, * if she loses, she bets 2 dollars on red and then stops. The roulette has 38 numbers from which 0 and 00 are green and the rest are red or black. When a gambler bets on red, the gambler wins if the ball stops at any of the red numbers. In addition, the payout when betting on colors is 1:1 (i.e. if one wins, one gets back double the money one bet). a) Find the probability she loses 3 dollars. b) Find the probability she won on the first bet given that she made 1 dollar. c) If X is the amount of money she won, find E[X]. d) Suppose the gambler changes her strategy and now bets 1 dollar every time on red and never stops. So, on every bet she either wins or loses a dollar. Find the expected number of bets she will make till she wins at least 3 out of 4 consecutive bets.
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Transcript

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00:01 So there are total 38 numbers of which two are green.
00:05 18 are red and 18 are black.
00:08 Let the probability that ball stops at red be.
00:14 Ball stops at red be r.
00:21 So r is 18 upon total is 38.
00:26 That is 9 upon 19.
00:29 So first, the probability that she loses three dollars so to lose three dollars to lose three dollars she should lose should lose the first game the first game and then she should also lose in the second and then stops the game so the probability that she loses the game is 1 minus r hence the probability is 1 minus r that is 9 upon 19 multiplied by 9 upon 19 which is 0 .2244.
01:42 Second the probability that she won on the first bet given she made one dollar let why let why be the event that she made one dollar so she won the first game and stops so wins one dollars and she loses the first game she wins first game she wins first game and she makes one dollar and she loses first game and wins second so she makes, loses $1 and wins two...
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