00:02
Here in this problem, given 65 .6 grams of a gas occupies 5 .60 liters at 2 atm and 273 kelvin.
00:14
We have to calculate the molar mass of the gas.
00:17
Also, we have to identify the gas.
00:20
Now, according to ideal gas equation, we can write pv is equal to nrt.
00:27
Here, p pressure of the gas, v volume of the gas, a number of most of the gas.
00:31
Are gas constant t temperature.
00:35
So we can write p is equal to n by v r t.
00:40
Now, n is number of moles of the gas, that is the mass of the gas divided by the molar mass of the gas times v r t.
00:53
So molar mass, m is wrt divided by pv...