A gas at 10 atm pressure occupies a volume of 10 litres at 300 K. It is allowed to expand at the constant temperature of 300 K under a constant external pressure till the volume equilibrates at 100 litres. Calculate the work done.
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In this case, the initial volume (V1) is 10 liters and the final volume (V2) is 100 liters. So, the change in volume (ΔV) is V2 - V1 = 100 liters - 10 liters = 90 liters. The problem does not specify the external pressure, but since the gas starts at 0 atm and Show more…
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