00:01
Okay, for this question we are going to utilize charles ' law to find our final temperature.
00:08
So charles ' law is v1 over t1 equals v2 over t2.
00:15
So initial volume divided by initial temperature equals the final volume divided by the final temperature.
00:23
We are solving in all of these questions for t2.
00:26
So we are going to manipulate our equation so that t2 is equal to v2 times t1 divided by v1.
00:38
So all four of our questions that they ask us are going to be set up in this format.
00:42
So problem number one, we are just going to plug some numbers in.
00:47
Okay so v2, our final volume that we are given is 1 .79 liters.
00:55
We multiply that by our initial temperature.
00:58
On all of these gas law problems our temperature does have to be in kelvin.
01:02
So zero celsius is 273 kelvin.
01:05
And then we are going to divide this by 4 .35 liters which is the initial volume that they gave us.
01:14
When we work this problem, obviously our liters cancel out.
01:17
We are left with kelvin as a unit.
01:20
We get an answer of 112 kelvin.
01:24
Obviously the question asks us to find this, our final temperature in degrees celsius.
01:29
So to get from kelvin to celsius we are going to subtract 273 which gives us a final answer of 161 degrees celsius.
01:38
That does have three sig figs which is what the question wants.
01:42
And so we are good to go there.
01:44
On number two, the final volume, v2 that they give us is 1 ,220 milliliters.
01:51
We do need to have this in liters.
01:53
So we are going to change that to 1 ,220 liters.
01:58
Again our initial temperature is 273 kelvin...