Question

A gas mixture consists of 30% carbon dioxide (CO2) and 70% nitrogen (N2) by volume. The mixture flows through a pipe of length 20 meters and a diameter of 0.1 meters at a flow rate of 0.05 m3/s. The diffusion coefficient of CO2 in N2 is 0.16 cm2/s, and the viscosity of the gas mixture is 2.3 x 10^-5 kg/ms. Determine the mole fraction of CO2 at the outlet of the pipe using Fick's law 

          A gas mixture consists of 30% carbon dioxide (CO2) and 70% nitrogen (N2) by volume. The mixture flows through a pipe of length 20 meters and a diameter of 0.1 meters at a flow rate of 0.05 m3/s. The diffusion coefficient of CO2 in N2 is 0.16 cm2/s, and the viscosity of the gas mixture is 2.3 x 10^-5 kg/ms. Determine the mole fraction of CO2 at the outlet of the pipe using Fick's law
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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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A gas mixture consists of 30% carbon dioxide (CO2) and 70% nitrogen (N2) by volume. The mixture flows through a pipe of length 20 meters and a diameter of 0.1 meters at a flow rate of 0.05 m3/s. The diffusion coefficient of CO2 in N2 is 0.16 cm2/s, and the viscosity of the gas mixture is 2.3 x 10^-5 kg/ms. Determine the mole fraction of CO2 at the outlet of the pipe using Fick's law
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Transcript

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00:01 Hello everybody here m o2 is equal to no2 into m o2 that is equal to m o2 that is equal to 30 kilo mole into 32 kg per kilo mole now it will become 960 kg in this way we can find out m n2 that is equal to 1120 kg and m co2 is taken as 320 kg and m co2 is taken as 32 kg and m c h4 can be written as 2840 that much kg total mass is equal to 840 that much kg so, m m is equal to m by nm so that is 2840 kg by 100 kilo.
01:29 So that is equal to 28 .40 kg per kilo -mol.
01:36 Now, app iron gas constant that is equal to i.
01:50 U by m m so from here we get 8 .314 whole divide by 28 .40 that is equal to 0 .292 specific volume or that is equivalent to density is equal to rt by row so from here we get it as 0 .01054 meter cube per kg so from here volume flow rate is equal to a into v that is pi d squared by 4 into v so we get it as 0 .000 0 .009425 meter cube per second...
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