Question

A gas originally occupying 10.1 L at 0.925 atm and 25°C is changed to 7.3 L at 1 atm. What is the new temperature? 40.1 °C 40.1 °C 232.8 °C 273 °C -232.8 °C 

          A gas originally occupying 10.1 L at 0.925 atm and 25°C is changed to 7.3 L at 1 atm. What is the new temperature? 40.1 °C 40.1 °C 232.8 °C 273 °C -232.8 °C

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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A gas originally occupying 10.1 L at 0.925 atm and 25°C is changed to 7.3 L at 1 atm. What is the new temperature? 40.1 °C 40.1 °C 232.8 °C 273 °C -232.8 °C
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Transcript

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00:01 Hello student, in this question we have to calculate the value of temperature.
00:05 For this we will use the ideal gas law that is pv is equals to nrt.
00:11 Now to find the value of t, we will rearrange the equation for t that is t is equal to pv upon nr.
00:22 Since the number of moles are assumed to be constant, we can write t1 is equals to p1v upon nr and t2 is equal to p2v by nr.
00:40 Now dividing t2 by t1, we get p2v upon nr whole upon p1v upon nr...
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