Question

A genetic experiment involving peas yielded one sample of offspring consisting of 434434 green peas and 134134 yellow peas. Use a 0.050.05 significance level to test the claim that under the same circumstances, 2525% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. Question content area bottom Part 1 What are the null and alternative hypotheses? A.Upper H 0 : p not equals 0.25 Upper H 1 : p greater than 0.25 Upper H 0 : p not equals 0.25H0: p≠0.25 Upper H 1 : p greater than 0.25H1: p>0.25 B.Upper H 0 : p equals 0.25 Upper H 1 : p not equals 0.25 Upper H 0 : p equals 0.25H0: p=0.25 Upper H 1 : p not equals 0.25H1: p≠0.25 Your answer is correct. C.Upper H 0 : p not equals 0.25 Upper H 1 : p equals 0.25 Upper H 0 : p not equals 0.25H0: p≠0.25 Upper H 1 : p equals 0.25H1: p=0.25 D.Upper H 0 : p equals 0.25 Upper H 1 : p less than 0.25 Upper H 0 : p equals 0.25H0: p=0.25 Upper H 1 : p less than 0.25H1: p<0.25 E.Upper H 0 : p equals 0.25 Upper H 1 : p greater than 0.25 Upper H 0 : p equals 0.25H0: p=0.25 Upper H 1 : p greater than 0.25H1: p>0.25 F.Upper H 0 : p not equals 0.25 Upper H 1 : p less than 0.25 Upper H 0 : p not equals 0.25H0: p≠0.25 Upper H 1 : p less than 0.25H1: p<0.25 Part 2 What is the test statistic? zequals=enter your response here (Round to two decimal places as needed.)

          A genetic experiment involving peas yielded one sample of offspring consisting of
434434
green peas and
134134
yellow peas. Use a
0.050.05
significance level to test the claim that under the same circumstances,
2525%
of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
Question content area bottom
Part 1
What are the null and alternative hypotheses?
A.Upper H 0 : p not equals 0.25 Upper H 1 : p greater than 0.25
Upper H 0 : p not equals 0.25H0: p≠0.25
Upper H 1 : p greater than 0.25H1: p>0.25
B.Upper H 0 : p equals 0.25 Upper H 1 : p not equals 0.25
Upper H 0 : p equals 0.25H0: p=0.25
Upper H 1 : p not equals 0.25H1: p≠0.25
Your answer is correct.
C.Upper H 0 : p not equals 0.25 Upper H 1 : p equals 0.25
Upper H 0 : p not equals 0.25H0: p≠0.25
Upper H 1 : p equals 0.25H1: p=0.25
D.Upper H 0 : p equals 0.25 Upper H 1 : p less than 0.25
Upper H 0 : p equals 0.25H0: p=0.25
Upper H 1 : p less than 0.25H1: p<0.25
E.Upper H 0 : p equals 0.25 Upper H 1 : p greater than 0.25
Upper H 0 : p equals 0.25H0: p=0.25
Upper H 1 : p greater than 0.25H1: p>0.25
F.Upper H 0 : p not equals 0.25 Upper H 1 : p less than 0.25
Upper H 0 : p not equals 0.25H0: p≠0.25
Upper H 1 : p less than 0.25H1: p<0.25
Part 2
What is the test statistic?
zequals=enter your response here
(Round to two decimal places as needed.)

Added by David M.

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