A genetic experiment involving peas yielded one sample of
offspring consisting of 441 green peas and 120 yellow peas. Use a
0.05 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
What is the test statistic?
Z= (round to two decimal
places)
What is the P-value?
P-value= (round to four decimal
places)
What is the conclusion about the null hypothesis?
Fail to reject the null hypothesis because the
P-value is greater than the significance level, α
Fail to reject the null hypothesis because the
P-value is less than or equal to the significance level, α.
Reject the null hypothesis because the P-value is
greater than the significance level, α
Reject the null hypothesis because the P-value is
less than or equal to the significance level,
α.
What is the final conclusion?
There is not sufficient evidence to support the claim that
less than 27% of offspring peas will be yellow.
There is sufficient evidence to support the claim that less
than 27% of offspring peas will be yellow.
There is sufficient evidence to warrant rejection of the claim
that 27% of offspring peas will be yellow.
There is not sufficient evidence to warrant rejection of
the claim that 27% of offspring peas will be yellow.