00:01
Hello everyone, we are going to understand this question.
00:05
Here, given in the question, given thickness of glass seed, thickness of glass seed that is represented by t, which is 1 .3 micrometer.
00:33
Or we can write 1 .3 into 10 to the power minus 6 meter.
00:40
Here, value of lambda 1.
00:42
That is given 519 nanometer or we can write 519 into 10 to the power minus 9 meter and value of lambda 2 that is given 605 .0 nanometer or we can write 605 .0 into 10 to the power minus 9 meter now minimum value of index of refraction that we have to find minimum value of index of refraction.
01:30
Minimum value of index of refraction that is represented by mu which we have to find.
01:46
Here, reflection from first surface, reflection from first surface, that is 2mut is equal to m into lambda 1.
02:17
And reflection from second surface, reflection from second surface, that is 2 into muu t, 2 mu t is equal to m minus 1 into lambda 2.
02:44
Now here we can see that 2 into mu t is same in both equations.
02:52
So we can write now that this is equation 1 and this is equation 2.
03:00
Now from equation 1 and 2, from equation 1 and 2, we can write m into lambda 1 is equal to m minus 1 into lambda 2...