A golfer, driving a golf ball off the tee, gives the ball a velocity of +40.1 m/s. The mass of the ball is 0.0449 kg, and the duration of the impact with the golf club is 4.77 x 10-3 s. (a) What is the change in momentum of the ball? (b) Determine the average force applied to the ball by the club.
Added by Jose Antonio E.
Step 1
0449 \, \text{kg}\) Initial velocity, \(u = 40.1 \, \text{m/s}\) Initial momentum, \(p_i = m \times u\) \[p_i = 0.0449 \times 40.1 = 1.8005 \, \text{kg m/s}\] Therefore, the change in momentum is \(1.8005 \, \text{kg m/s}\). Show more…
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