A golfer keeps track of his score for playing nine holes of golf​ (half a normal golf​ round). His mean score is with a standard deviation of. Assuming that the second 9 has the same mean and standard​ deviation, what are the mean and standard deviation of his total score if he plays a full 18​ holes?
Added by Altagracia G.
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Given that the mean score for 9 holes is 86, the mean score for 18 holes will be 86 + 86 = 172. Show more…
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A golfer keeps track of his score for playing nine holes of golf (half a normal golf round). His mean score is 78 with a standard deviation of 9. Assuming that the second 9 has the same mean and standard deviation, what are the mean and standard deviation of his total score if he plays a full 18 holes? The mean of his total score is . (Round to the nearest integer as needed.)
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A golfer keeps track of his score for playing nine holes of golf (half a normal golf round). His mean score is 85 with a standard deviation of 11 . Assuming that the second 9 has the same mean and standard deviation, what is the mean and standard deviation of his total score if he plays a full 18 holes?
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