A government task force suspects that some manufacturing companies are in violation of federal pollution regulations with regard to dumping a certain type of product. Twenty firms are under suspicion but not all can be inspected. Suppose that 3 of the firms are in violation. (a) What is the probability that inspection of 5 firms will find no violations? (b) What is the probability that the plan above will find two violations?
Added by Jennifer L.
Step 1
This can be done using the combination formula C(n, k) = n! / [k!(n-k)!], where n is the total number of items, k is the number of items to choose, and "!" denotes factorial. So, C(20, 5) = 20! / [5!(20-5)!] = 15504. Show more…
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A government task force suspects that some manufacturing companies are in violation of federal pollution regulations with regard to dumping a certain type of product. Twenty firms are under suspicion but all cannot be inspected. Suppose that 3 of the firms are; in violation. (a) What is the probability that inspection of 5 firms finds no violations? (b) What is the probability that the plan above will find two violations?
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