A gun is shot into a 0.50 kN block which is hanging from a rope of 1.8 m long. The weight of the bullet is equal to 5 N with a muzzle velocity of 320 m/s. How high will the block swing after it was hit by the bullet?
Added by Victoria T.
Step 1
8 m: Initial momentum = 500 N * 1.8 m = 900 N·m Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 55 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A gun is shot into a 0.50 KN block which is hanging from a rope of 1.8m long. The weight of the bullet is equal to 5N with a muzzle velocity of 320m/s. How high will the bag swing after it was hit by the bullet?
Dominique Jan T.
A gun is shot into a 0.50 kg block which is hanging from a rope of 1.8 m long. The weight of the bullet is equal to 5 N with a muzzle velocity of 320 m/s. How high will the bag swing after it was hit by the bullet?
Sri K.
A rifle bullet with mass 8.00 g strikes and embeds itself in a block with mass 0.992 kg that rests on a frictionless, horizontal surface and is attached to a coil spring $(\textbf{Fig. P8.79})$. The impact compresses the spring 15.0 cm. Calibration of the spring shows that a force of 0.750 N is required to compress the spring 0.250 cm. (a) Find the magnitude of the block's velocity just after impact. (b) What was the initial speed of the bullet? Figure P8.79 (CANT COPY FIGURE)
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD