9 \times 10^{3} \, C$ of charge to pass through the hair dryer.
Given:
Total charge, $Q = 1.9 \times 10^{3} \, C$
Current, $I = 9.1 \, A$
We know that $Q = I \times t$, where $t$ is the time taken.
Therefore, $t = \frac{Q}{I} = \frac{1.9 \times 10^{3}}{9.1} =
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