Question

A heat engine operates in a Carnot cycle between 80.0°C and 350°C. It absorbs 21000 J of energy per cycle from the hot reservoir. The duration of each cycle is 1.00 s. (a) What is the mechanical power output of this engine? (b) How much energy does it expel in each cycle by heat? 

          A heat engine operates in a Carnot cycle between 80.0°C and 350°C. It absorbs 21000 J of energy per cycle from the hot reservoir. The duration of each cycle is 1.00 s. (a) What is the mechanical power output of this engine? (b) How much energy does it expel in each cycle by heat?
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A heat engine operates in a Carnot cycle between 80.0°C and 350°C. It absorbs 21000 J of energy per cycle from the hot reservoir. The duration of each cycle is 1.00 s. (a) What is the mechanical power output of this engine? (b) How much energy does it expel in each cycle by heat?
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Transcript

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00:01 In this question it is given the heat engine operates in a car not cycle and that to in between the 80 degrees celsius to 350 degrees celsius it observes it absorbed 21 ,000 joules of energy per cycle so duration of each cycle is one second so it is asked in the air part what is the mechanical power that what we have to calculate so we know that the efficiency of car not engine is given by 1 minus tc divided by th okay so tc is given which is 80 degrees celsius so 1 minus this is 80 degrees celsius and 80 degrees celsius in kelvin that is equivalent to so this is equivalent to 300 and 53 kelvin divided by ths so this is 350 so plus 273 that is 623 in kelvin so this is equivalent to 0 .33 this is the efficiency so if this is the efficiency then what is the maximum power output? so we have to calculate the power max that is equivalent to work done of the engine and that to max and it is multiplied with e and this is whole divided with one second so this value is 0 .433 multiplied by 21 kilojoules and whole divided with this is one second so we get this value this power max that is equivalent to 9 .10 below so this will be the answer for the a part now we are going to solve the v part.
01:33 So we know that efficiency is also equals to 1 minus qc divided by qh modulus.
01:41 Clear? so energy expelled us.
01:44 So we know that modulus of qc, that is equal to modulus of qh times 1 minus e...
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