A heat engine performs 200 J of work in each cycle and has an efficiency of 30.0%. For each cycle, how much energy is (a) taken in and (b) expelled by heat?
Added by Amy G.
Step 1
Given that the work done in each cycle is 200 J and the efficiency is 30%, we can use the formula for efficiency: Efficiency = Work output / Heat input. Efficiency = 0.30 = 200 / Heat input. Heat input = 200 / 0.30 = 666.67 J. Show more…
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