00:01
Hello students here is a given question and the question says what is a heavy car of mass 200 kilograms tabling 10 meter per second has a head on collision with a sport car b 500 kilograms is what car stopped dead on colliding then what was the velocity of car b okay this is the situation let's suppose this is the car a and this is the car b car b the velocity of the car is like this and velocity of the car b is like this okay this is v a is equal to 10 meter per second and m a is equal to let's suppose this is the initial velocity that that's why we have to take this is ua okay and ma is equal to 200 kilograms okay and here is the velocity u b is equal to given that is u b okay what is this we have to find out this and now what is the mb? mb will be equal to 500 kilograms.
01:06
After they are colliding like this.
01:10
Then the final velocity of the va is equal to vb is equal to 0.
01:15
Then here the act means if we can assume the system of both of the car, then as external on the system is equal to 0, then we also apply in the conservation of linear movement.
01:28
Momentum, okay? and we know that the final momentum will be zero, okay? we can return it like this.
01:35
M -a -u -a plus m -v -u -b.
01:39
This is the initial momentum is equal to final momentum m -a -v -a plus m -b -b -b, right? then this will be or this will zero just because of both are stopped.
01:51
What is the m -a, that is 200 multiplied by u -a, u -a is given 10, okay? and plus m -b -a mb is 500 and multiplied by the ub.
02:03
We have to find out the ub how much and this is the equal to 0.
02:08
Let's solve this...