A helicopter starts from rest at point a and travels along...

A helicopter starts from rest at point A and travels along the straight-ine path with a constant acceleration a.lf the speed v= 22 m/swhen the altitude of the helicopter is h= 47 m, determine the values of i. ".0, and 6 as measured by the tracking device at 0. At thisinstant, 0 = 39, and the distance d = 144 m. Neglect the small height of the tracking device above the ground.

Transcript

00:01 Hello students we are given the following scenario the helicopter is present at point b and the detector is at point o then in triangle o a b we will have r sine theta equals to h substituting the values we get r sine 40 degree equals to 35 which gives us r equals to 54 .45 meters now by vector addition rule we will get ab vector equal to oa square plus ob square minus 2 oa to o b to o b pos theta under root.

00:53 Substituting the values we get or a b vector magnitude equals to 142.

01:03 65 meters now let's find sign of alpha so using the sign rule we will have ob upon sine alpha will be equal to ab upon sine 40 which gives us sine alpha will be equal to 54 .45 upon 14 .6 sign of 40 degree solving this we will get the value of angle alpha will be equal to 14 .18 degrees now to calculate the acceleration of the helicopter we will use the equation of motion v square minus u squared equals to 2 a s and substituting values we will get 35 square minus 0 square will be equal to 2 into acceleration in into 142 .65.

02:12 S is the distance covered that is ab.

02:19 Solving this we get the acceleration equals to 4 .29 meter per second square.

02:28 Now the r and theta components of the velocity and acceleration are as shown.

02:35 So we can write vr equals to v sine 90 minus theta.

02:42 Minus alpha which is equal to 35 sign 90 minus 40 minus 14 point 18 solving this we get vr equals to 20 .48 meter per second now we use vr equals to minus r dot and thus we can write minus r dot will be equal to 20 .448 meter per second which gets us r dot will be equal to minus 20 .48 meter per second.

03:27 Next we can write v theta will be equal to v cost of 90 minus theta minus alpha which is equal to 35 into cost of 90 minus 40 minus 14...

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