A Hertzian dipole is 10 cm long. If the 10 MHz current flowing through it is 2 A, what is the field strength 20 km away from the dipole, in a direction of maximum radiation? Select one: A. 0 N/C B. 6.3 x 10^-3 N/C C. 6.3 x 10^-5 N/C D. 1 x 10^-3 N/C
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In this case, I0 = 2 A, l = 10 cm = 0.1 m, and λ = c/f = 3 x 10^8 m/s / 10 MHz = 30 m. Therefore: I = (2π/3) * (2 * 0.1/30)^2 = 2.22 x 10^-5 W/m^2 Show more…
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