00:01
In this problem, we are given that there is a hockey puck, and this is given an initial velocity of 5 meter per second.
00:10
And this is moving on a surface on which the coefficient of kinetic friction between the puck and the surface that is given as 0 .05.
00:23
So this is very low and that's generally meant that this hockey park is moving on the surface of ice.
00:31
And we are required to determine the distance this hockey pack will slide before it comes to rest.
00:38
So let's say the distance it travels is s and as it comes to rest, its final velocity, that will be zero meter per second.
00:46
So if we observe the free body diagram of this hockey pack, we see that the weight will be balanced by the normal form.
00:53
So the normal force will act in the upward direction and that will be balanced by the weight given by this expression, which is mass times acceleration due to gravity.
01:04
And we will use this expression to get the friction force, which is acting as a kind of resistive force for this hockey puck, and that will act on the left side, which is in the opposite direction of the motion of this puck.
01:18
So this friction force will be mu times normal force, which is mass times acceleration due to gravity, and that will be the opposite direction due to gravity...