00:01
Determine the magnitude and direction of velocity of the second puck after our collision.
00:07
Okay, so to find our speed of our second puck, we want to think about our initial momentum.
00:13
Our initial momentum is mass one times our initial velocity one, so it'll be 0 .16 times two.
00:21
So, give us 0 .16 times two gives us 0 .32 in the i -hat direction.
00:27
Now, our final momentum, p final, is mass one v one plus mass two v two.
00:35
Mass one is our 0 .16.
00:38
We have our velocity two, and that's going to be multiplied by our collision, which will be 1 .5.
00:51
So, it's going to be 1 .5, let's say, cosine of our angle 30 degrees i -hat plus 1 .5 sine 30 degrees j -hat plus 0 .17 times v two cosine theta minus v two sine theta.
01:09
So, we can go ahead and rewrite this.
01:12
We have 0 .6, well, let's go ahead and write down in our different directions.
01:16
We have 1 .5 cosine of 30, that gives us 1 .29 times 0 .16, so 0 .20.
01:26
That'll give us 0 .20 i -hat plus, now plugging in our sine, plus 0 .12 j -hat.
01:39
Then that will, right, plus, and now we can just distribute this on both sides.
01:50
Now, we can set our initial momentum equal to our final momentum.
01:57
And so, doing so, that will be 0 .32 i -hat equal to our 0 .20 i -hat plus 0 .12 j -hat plus 0 .17 v two cosine theta i -hat minus 0 .17 v two sine theta j -hat...