A home improvement company is interested in improving customer satisfaction rate from the 68% currently claimed. The company sponsored a survey of 237 customers and found that 173 customers were satisfied. Determine whether sufficient evidence exists that the customer satisfaction rate is different than the claim by the company. What is the test statistic $z$? What is the $p$-value? Does sufficient evidence exist that the customer satisfaction rate is different than the claim by the company at a significance level of $\alpha = 0.1$? Round $z$ to two decimal places. Round the $p$-value to three decimal places.
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68$ be the claimed customer satisfaction rate. Let $n = 237$ be the number of customers surveyed. Let $x = 173$ be the number of satisfied customers. The sample proportion is $\hat{p} = \frac{x}{n} = \frac{173}{237} \approx 0.7299$. Show more…
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