A horizontal beam of light enters a $45^{\circ}-90^{\circ}-45^{\circ}$ prism at the center of its long side, as shown in Figure $26-51$. The emerging ray moves in a direction that is $34^{\circ}$ below the horizontal. What is the index of refraction of this prism?
Added by Michael P.
Step 1
Step 1: Use Snell's Law to relate the incident angle, angle of refraction, and the indices of refraction: $n \sin(\text{incident angle}) = n' \sin(\text{angle of refraction})$ Show more…
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