00:01
For this question, a hospital director wants to test whether the percentage of uninsured patients is less than 32%.
00:08
So that is a test that the proportion is less than .32.
00:14
And we're asked to test this at a significance level of 0 .05.
00:18
And to do so, we have a sample of 140 patients.
00:22
And of the 140, it was found that 35 were uninsured.
00:27
The first step here is to identify the hypotheses.
00:31
The first the null hypothesis would be that the proportion is 32%, or 0 .32.
00:41
And the alternative is what's wanting to be tested here is that the proportion is less than 0 .32.
00:49
And when we have a large sample to estimate the proportion with, our test statistics based on the standard normal distribution.
00:57
It's calculated as the sample proportion, denoted p bar minus the null hypothesized proportion, divided by the square root of the null proportion times 1 minus the null proportion over the sample size...