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A hot-rolled steel has a yield strength of Syt = Syc = 100 kpsi and a true strain at fracture of ?f = 0.55. Calculate the factor of safety (n) for the following stress states by using both MSS and DE theory: (a) ?x = -50 kpsi, ?y = -50 kpsi, ?xy = -30 kpsi (b) ?x = -50 kpsi, ?y = 0 kpsi, ?xy = -30 kpsi (c) ?x = 0 kpsi, ?y = 50 kpsi, ?xy = 30 kpsi

          A hot-rolled steel has a yield strength of Syt = Syc = 100 kpsi and a true strain at fracture of ?f = 0.55. Calculate the factor of safety (n) for the following stress states by using both MSS and DE theory:
(a) ?x = -50 kpsi, ?y = -50 kpsi, ?xy = -30 kpsi
(b) ?x = -50 kpsi, ?y = 0 kpsi, ?xy = -30 kpsi
(c) ?x = 0 kpsi, ?y = 50 kpsi, ?xy = 30 kpsi

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$A hot-rolled steel has a yield strength of Syt = Syc = 100 kpsi and a true strain at fracture of ?f = 0.55. Calculate the factor of safety (n) for the following stress states by using both MSS and DE theory: (a) ?x = -50 kpsi, ?y = -50 kpsi, ?xy = -30 kpsi (b) ?x = -50 kpsi, ?y = 0 kpsi, ?xy = -30 kpsi (c) ?x = 0 kpsi, ?y = 50 kpsi, ?xy = 30 kpsi$

Added by Jose Miguel H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Adi S

09/18/2023

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The MSS theory states that failure occurs when the maximum shear stress in a material exceeds the shear stress at yield in a simple tension test. The DE theory, also known as the von Mises theory, states that failure occurs when the distortion energy per unit Show more…

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A hot-rolled steel has a yield strength of Syt = Syc = 100 kpsi and a true strain at fracture of εf = 0.55. Calculate the factor of safety (n) for the following stress states by using both MSS and DE theory: (a) σx = -50 kpsi, σy = -50 kpsi, τxy = -30 kpsi (b) σx = -50 kpsi, σy = 0 kpsi, τxy = -30 kpsi (c) σx = 0 kpsi, σy = 50 kpsi, τxy = 30 kpsi

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